2.4t^2-62t=0

Solution for 2.4t^2-62t=0 equation:

2.4t^2-62t=0

a = 2.4; b = -62; c = 0;
Δ = b2-4ac
Δ = -622-4·2.4·0
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-62}{2*2.4}=\frac{0}{4.8}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+62}{2*2.4}=\frac{124}{4.8}
=25+1/1.2
$